Answer:
The student is expected to spend <em>15.4 hours </em>doing homework
Step-by-step explanation:
The scattered plot shows there is a close correlation between the variables. A line of best fit will go through the 'center' of the points. Since we are not required to find an exact line, we'll draw it in red color as shown below
To know the equation of that line, we must take two clear points of it from the graph. We'll pick (28,4) and (4,25)
The equation of a line, given two points (a,b) and (c,d) is
![\displaystyle y-b=\frac{d-b}{c-a}(x-a)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-b%3D%5Cfrac%7Bd-b%7D%7Bc-a%7D%28x-a%29)
Using the selected points
![\displaystyle y-4=\frac{25-4}{4-28}(x-28)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-4%3D%5Cfrac%7B25-4%7D%7B4-28%7D%28x-28%29)
Simplifying and computing results, the equation is
![\displaystyle y=-\frac{7}{8}x+\frac{57}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D-%5Cfrac%7B7%7D%7B8%7Dx%2B%5Cfrac%7B57%7D%7B2%7D)
Using that equation, we can predict how many hours the students will spend doing homework if they spend 15 hours watching TV
=15.4 hours
So the student is expected to spend 15.4 hours doing homework
Answer:
No, It's false.
Step-by-step explanation:
In the long history of the United States, only one president, George Washington, did not represent a political party.
Answer:
34
Step-by-step explanation:
that what i think
Answer:
1 100/200
Step-by-step explanation:
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.