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Kazeer [188]
3 years ago
11

Ben has a part time job at the fun station. Suppose he worked 13.5 hours last week and $81. How much does Ben earn per hour

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

To get the answer, you will just use this operation: Division.
Let's divide it. 81 ÷ 13.5 = 6.

So, the answer is
Ben earns $6 per hour at the fun station.

azamat3 years ago
3 0

Answer:  Ben earn $6 per hour.

Step-by-step explanation:  Given that Ben has a part time job at the fun station. He worked 13.5 hours last week and $81.

We are to find the earning of Ben per hour.

We will be using the UNITARY method to solve the problem.

We have

Earning of Ben in 13.5 hours = $81.

Therefore, the earning of Ben in 1 hour is given by

\$\dfrac{81}{13.5}=\$6.

Thus, Ben earn $6 per hour.

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One hundred items are simultaneously put on a life test. Suppose the lifetimes
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Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
4 years ago
3/4(x + 3) = 9<br><br><br> How do I solve this
Sonbull [250]

Answer:

x = 10

Step-by-step explanation:

so first distribute the 3/4 to everything on the inside

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now subtract 1 1/2 on both sides

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Now divide both sides by 3/4

x = 7 1/2 divided by 3/4

x = 15/2 divided by 3/4

x = 15/2 times 4/3

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3 years ago
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Romashka [77]

His sum should be more than 48.

I know because if you throw away the decimal pieces
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7 0
3 years ago
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timofeeve [1]

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