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3 years ago

6

What is the sum of 3/5

2 answers:

Tatiana [17]3 years ago

6 0

2 or 3 so here you go dude

Nitella [24]3 years ago

3 0

2 or something like that I'm not the smartest but I think it is 2

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How do I solve this?

Ivenika [448]

$\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}$

$\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2$

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3 years ago

Graph y = -½ x -3 mathematics

Dominik [7]

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3 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

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masha68 [24]

Answer:

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Step-by-step explanation:

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