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ZanzabumX [31]
3 years ago
6

Use the web below to take notes on the changes women experienced in the 1920s

Mathematics
1 answer:
leonid [27]3 years ago
8 0
Electricity system slime
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Sixteen pages longer than a quarter the length of the first draft:
Ronch [10]
IS there supposed to be an attachment i could look at?
8 0
4 years ago
Using the attached link below.
Serhud [2]

\text{Use the Pythagorean theorem:}\\\\r-hypotenuse\\\\r^2=7^2+5^2\\\\r^2=49+25\\\\r^2=74\to r=\sqrt{74}

\sin=\dfrac{opposite}{hypotenuse}\\\\\cos=\dfrac{adjacent}{hypotenuse}\\\\\tan=\dfrac{opposite}{adjacent}\\\\\cot=\dfrac{adjacent}{opposite}\\\\\text{We have}\\\\for\ the\ angle\ y:\\\text{opposite = 7}\\\text{adjacent = 5}\\\text{hypotenuse = }\ \sqrt{74}\\\\for\ the\ angle\ x:\\\text{opposite = 5}\\\text{adjacent = 7}\\\text{hypotenuse = }\ \sqrt{74}

\csc x=\dfrac{1}{\sin x}\\\\\sec x=\dfrac{1}{\cos x}

A.\\\\\sin x=\dfrac{5}{\sqrt{74}}=\dfrac{5\sqrt{74}}{74}\\\\\csc y=\dfrac{1}{\frac{7}{\sqrt{74}}}=\dfrac{\sqrt{74}}{7}\\\\B.\\\\\tan x=\dfrac{5}{7}\\\\\cot y=\dfrc{5}{7}\\\\C.\\\\\cos x=\dfrac{7}{\sqrt{74}}=\dfrac{7\sqrt{74}}{7}\\\\\sec y=\dfrac{1}{\frac{5}{\sqrt{74}}}=\dfrac{\sqrt{74}}{5}

D.\\\sin\theta=\dfrac{2}{3}\\\\\sin^2\theta+\cos^2\theta=1\to\left(\dfrac{2}{3}\right)^2+\cos^2\theta=1\\\\\dfrac{4}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{4}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{5}{9}\to\cos\theta=\sqrt{\dfrac{5}{9}}\to\cos\theta=\dfrac{\sqrt5}{3}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\to\tan\theta=\dfrac{\frac{2}{3}}{\frac{\sqrt5}{3}}=\dfrac{2}{3}\cdot\dfrac{3}{\sqrt5}=\dfrac{2}{\sqrt5}=\dfrac{3\sqrt5}{5}

6 0
3 years ago
Help please!!! Thank you
ANTONII [103]

Answer:

Option (G)

Step-by-step explanation:

Let the length of the race = a miles

Since, Speed = \frac{\text{Distance}}{\text{Time}}

Time taken to cover 'a' miles with the speed = 12 mph,

Time taken 't_1' = \frac{a}{12}

Time taken to cover 'a' miles with the speed = 11 mph,

Time taken 't_2' = \frac{a}{11}

Since the time taken by David to cover 'a' miles was 10 minutes Or \frac{1}{6} hours more than the time he expected.

So, t_2=t_1+\frac{1}{6}

\frac{a}{11}=\frac{a}{12}+\frac{1}{6}

\frac{a}{11}-\frac{a}{12}=\frac{1}{6}

\frac{12a-11a}{132}=\frac{1}{6}

a = 22 mi

Therefore, distance of the race = 22 mi

Option (G) is the correct option.

6 0
3 years ago
Manny took a math test. The test started at 12:53 PM, and ended at 1:23 PM. how long did his test last?
liraira [26]

Answer:

Step-by-step explanation:

the test lasted :

23 minutes+7=  30 min

12z;53 =7 min will be 1 pm

8 0
3 years ago
In 2002, the temperature on the first day of summer was 79°F. This is 4°F less than it was on the first day of summer the previo
kap26 [50]

Answer:

  C. In 2001, the temperature was 83°F.

Step-by-step explanation:

  79 is 4 less than 83.

The temperature in 2001 was 83 °F.

5 0
3 years ago
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