The family needs 4 days to cover 1,400 miles
Answer:
5 ≥ 9*.15 + x*.25
He can buy up to 14 candies
Step-by-step explanation:
Total money ≥number of peppermints * cost per peppermint + number of sour candies * cost per sour candy
We know he has 5 dollars. He bought 5 peppermints at $.15 cents each and x sour candies at $.25 each
Substituting in
5 ≥ 9*.15 + x*.25
5≥1.35 + .25x
Subtract 1.35 on each side
5-1.35 ≥ 1.35-1.35+.25x
3.65≥.25x
Divide by .25 on each side
3.65/.25 ≥ .25x/.25
14.6 ≥ x
He can buy up to 14 candies. You can't buy part of a candy
Its A. x=4
procedure: 3*equation1 - 2*equation2 ⇒ x=4
1) cluster
2) outlier
3) association
4) trend line
5) scatter plot
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
