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romanna [79]
2 years ago
5

Minor arc KL measures 135°. Circle O is shown. Line segments K O and O L are radii. Which is the radian measure of central angle

KOL? StartFraction 3 pi Over 8 EndFraction radians StartFraction 3 pi Over 4 EndFraction radians StartFraction 7 pi Over 8 EndFraction radians StartFraction 13 pi Over 5 EndFraction radians
Mathematics
2 answers:
snow_lady [41]2 years ago
3 0

StartFraction 3 pi Over 4 EndFraction radians

Step-by-step explanation:

Pi radians is equal to 180°

Given the minor arc angles as 135°, change this value to pi radians

180° =π radians

135° = ?

Cross multiply

135° * π radians / 180°

=135/180 *  π radians

=3 π/4  radians

Learn More

Changing degrees to radians :brainly.com/question/12095161

Keywords: minor arc, measure, circle, line segment, radii, central angle

#LearnwithBrainly

katrin [286]2 years ago
3 0

Answer: B. 3 pi/4 radians

Step-by-step explanation:

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30-[11+{18-(48÷8×2)}+7]+15
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Question 1 (1 point)
olga55 [171]

Answer:

1) 2y^{2}+4y-9

2) 18x^{5}y^{4}z

3) 6x^{5}-12x^{4}+9x^{3}

4) 40

5) x^{3}-7x^{2}+3x+36


Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}

4) (4a+5)^{2} is a square of a sum, then, by definition you have:

(a+b)^{2}=a^{2}+2ab+b^{2}

Then:

(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

5)  Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36

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