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4 years ago

What type of line is the graph of x = -2

Mathematics

2 answers:

artcher [175]4 years ago

8 0

The answer is vertical line

Anarel [89]4 years ago

5 0

X = -2

is an equation represented be a straight vertical line parallel to the y-axis

and normal to the x-axis at the point (-2,0)

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Write an expression that is equivalent to - 0.5(14a - 22) .

PSYCHO15rus [73]

$\textsf{Hey \: there}$

<h2>QUESTION</h2>

$\mathsf{-0.5(14a - 22)}$

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

$\mathsf{(-0.5)(14a) + (-0.5)( -22)}$

<h2>SOLVING FOR OUR ANSWER</h2>

$\mathsf{(0.5)(14a) = - 7a} \\ \\ \mathsf{( - 0.5)( - 22) = 11}$

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

$\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{ \bf- 7a + 11}}} \checkmark$

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

$\dfrac{\frak{LoveYourselfFirst}}{:)}$

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

$\text{a(b + c)} \\ \text{a(b) + a(c)} \\ \text{a(b) = ab} \\ \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}$

5 0

3 years ago

Read 2 more answers

the number if baskets nikki can make varies directy with the time she spends making the baskets she can make 4 baskets in 1/2 an

Amanda [17]

Answer:

40 baskets

Step-by-step explanation:

Find out how many baskets she can make in an hour. Since she makes 4 in 1/2 an hour, multiply 4 by 2 to find out how much she makes in an hour. She makes 8 baskets an hour, so multiply 8 by 5. 8 x 5 = 40.

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to

Natalka [10]

Answer:

A and b

Step-by-step explanation: Because ....

7 0

3 years ago

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The students in Brenna's grade voted to select a guest speaker. 15 students voted for a

DochEvi [55]

Answer:

25% of students voted for the athlete

Step-by-step explanation:

First you need to know how many students are in total. In this case there is 60, 15+45

Then you write it as a fraction

$\frac{15}{60}$

because 15 voted for athlete out of the 60 students.

After this you need to divide 15÷60 which is . 25 then you transform that number into a percent which is 25%

5 0

3 years ago

. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting

SashulF [63]

Answer:

The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;

The change in the call waiting time is not statistically significant

Step-by-step explanation:

The given call waiting times are;

24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77

19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27

From the data we have;

The mean waiting time before the downsize, $\overline x_1$ = 18.7895

The mean waiting time before the downsize, s₁ = 2.705152

The sample size for the before the downsize, n₁ = 20

The mean waiting time after the downsize, $\overline x_2$ = 19.5125

The mean waiting time after the downsize, s₂ = 3.155945

The sample size for the after the downsize, n₂ = 20

The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20 - 2 = 38

df = 38

At 95% significance level, using a graphing calculator, we have; $t_{\alpha /2}$ = ±2.026192

The t-confidence interval is given as follows;

$\left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}$

Therefore;

$\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}$

(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)

The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668

By approximation, we have;

The 95% CI = -2.61 < μ₂ - μ₁ < 1.16

Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.

6 0

3 years ago