Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
i think it is 1/26
Step-by-step explanation:
Answer:
Step-by-step explanation:
First question 1 = 0.3 = 0.7
Second question 60/5=12 so 12 hours
Third question first find lcm so 6
2 3/6 and 7 2/6
2.5 + 2.5 = 5 so 2 cakes
Fourth question
729/14 um calculator but ok 729/14=52.07 so 52.1
You said you'd report me if i only did 3,2,or 11 but i did 4 so i think im fine
Answer:
See attached. Line for x<5.
Step-by-step explanation:
Solve the equation for x. Remember that the "<" and ">" signs are reversed when dividing or multiplying by a negative value.
