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2 years ago

20) What is the slope of the line that is perpendicular to the line of the given equation?

1 answer:

4 0

Perpendicular lines have slopes that are opposite signs and reciprocals.
Example: If one line has a slope of 5/3, then the perpendicular slope is -3/5.

In your case, your first line has a slope of -1/5. The perpendicular slope will be positive and will be 5/1.

The slope of a line perpendicular to the given one is 5.

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winthrop has $4.40 worth of nickles and dimes. If winthrop has 3.5 times as many nickles as he has dimes, how many dimes does he

Aneli [31]

Answer:

Step-by-step explanation:

If n is number of nickles and d is number of dimes:

5n + 10d = 440

n = 3.5d

Substitute:

5(3.5)d + 10d = 440

17.5d + 10d = 440

27.5d = 440

d = 16

6 0

3 years ago

If x is a rational number and y is the opposite of x,why do x y have the same absolute value?

olga2289 [7]

They have the same absolute value because all opposites have the same absolut value because they both are the same distance from zero

5 0

3 years ago

Helppppp meeee plzzzzz

Slav-nsk [51]

Answer:

Angle B is 41 degrees

Step-by-step explanation:

1) find the supplement of the 113 degree angle; it is 180-113, or 67, degrees.

2) recognizing that the sum of the interior angles of a triangle is 180 degrees, add up 67 and 72 degrees, obtaining 139 degrees, and subtract this sum from 180 degrees:

180 degrees - 139 degrees = 41 degrees (answer)

The steps are outlined above; the end result is that <B is 41 degrees.

6 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

-16 -27 21 -19 14 -3 find the mean of the integers

anzhelika [568]

Answer:

-5

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers