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2 years ago

Is 3/5 and 6/8 proportional

2 answers:

3 0

3/5 and 6/8 are not proportional as even though 3 goes into 6 evenly, 5 does not go into 8 evenly so that makes it disproportional.

Anuta_ua [19.1K]2 years ago

3 0

No 3/5 and 6/8 is not proportional.

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A team won 1/4 of its games. If they played 20 games, how many did they win?

svetlana [45]

Answer:

Step-by-step explanation:

20 divided by 4 = 5

1 x 5 = 5

8 0

2 years ago

Read 2 more answers

Kyle is making 9 birdhouses. He uses 8 nails for each birdhouse. If Kyle has a box of 100 nails, how many nails will he have lef

iragen [17]

9 x 8 = 72
100 - 72 =28

Hope this helps

7 0

2 years ago

Tan(a)+cot(b) simplify please.

Hitman42 [59]

Answer:

tan a + cot b

Step-by-step explanation:

It's already simplified.

There are alternate forms like

$sec(a)csc(b)cos(a-b)\\\\sec(a)csc(b)[sin(a)sin(b)+cos(a)cos(b)]\\\\\frac{sin (a)}{cos (a)} +\frac{cos(b)}{sin(b)}$

5 0

2 years ago

Please can I have some more help sorry

sineoko [7]

Answer:

What are you asking?

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Anybody know the correct answer?

earnstyle [38]

Since $\csc^2{x}=\frac{1}{\sin^2{x}}$ and $\cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}$ , we can rewrite the right side of the equation as

$\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}$

Using the identity $\sin^2{x}+\cos^2{x}=1$ , we can subtract $\cos^2{x}$ from either side to obtain the identity $\sin^2{x}=1-\cos^2{x}$

substituting that into our previous expression, the right side of our equation simply becomes

$\frac{\sin^2{x}}{\sin^2{x}}=1$

We can now write our whole equation as

$3\tan^2{x}-2=1$

Adding 2 to both sides:

$3\tan^2{x}=3$

dividing both sides by 3:

$\tan^2{x}=1$

$\tan{x}=\pm1$

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0

2 years ago