Answer:
Radius = 7.995944341
Step-by-step explanation:
You use the circumference formula. C=2πr
Since you have the circumference 50.24 cm. You plug in the circumference.
50.24 = 2πr
You divide by 2 and get 25.12.
25.12 = πr
Then, you divide 25.12 by π.
Your answer is
7.995944341 = r
Answer:
I believe it is C because i heard of that one before
Answer:
The Volume of large cone is 19.545 
greater than the smaller cone
Step-by-step explanation:
Given:
Size of the small cone = 3.5 inches
Diameter of the small cone = 3 inches
Size of the large cone = 3.5 inches
Diameter of the small cone = 3 inches
To Find:
How much greater, to the nearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone = ?
Solution:
Volume of the small cone :
Radius = 
Radius = 
Radius = 1.5 inches
volume of the cone =
substituting the values,
=>
=>
=> 16.485
Volume of the large cone :
Volume of the large cone :
Radius =
Radius = 
Radius = 2.25 inches
volume of the cone =
substituting the values,
=>
=>
=>36.06
Now ,
volume of small cone - volume of large cone
=>36.06 - 16.485
=>19.545
Answer:
0.45
Step-by-step explanation:
The correlation coefficient is used to measure the relationship between how two variables change. In this question, the two variables are cars speed and gas mileage. Since the speedometers were wrong as they were 5 mph too high in a constant manner, then the correlation between how changes in speed affect gas mileage will not be changed.
For example, if we are measuring how an increase of 15 mph decreased gas mileage, we are looking at the change in speed and it is the same if we start with 75 mph and then increase speed to 90 mph, or if we start with 45 mph and then increase to 60 mph. The change in speed for both cases will remain unchanged at 10 mph.
Now, since we have seen that the change in speed remains unchanged and since correlation coefficient is a measure of the relationship between how two variables change, then the new value of the correlation coefficient will remain the same as 0.45.
