Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, the parameters are:

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103
The probability of that occurring is 0%. There are 6 sides in a typical dice, which means the probability of rolling a 2 is 1/6th. (1/6)^1000 will give you the probability of rolling a 2 exactly 1000 times. (1/6)^1000 equates to 0%.
Answer:
decrease by 50%
Step-by-step explanation:
Decreased by 60% = (100%-60%)x = 0.4x.
Decreased by 20% = (100%-20%)x = 0.8x.
initial fraction, and we can see that denominator will increase 2 times, so fraction will decrease 2 times, or decrease by 50%.
Answer:
-2. 46
- 9.54
Step-by-step explanation:
- 2x²+12x-7=0
- 2x²+12x+18= 25
- 2*(x²+6x+9)=25
- 2*(x+6)²= 5²
- x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
- x+6= -5√2/2 ⇒ x= -5√2/2 -6 ≈ - 9.54