Answer:
Only option B is correct, i.e. all real values of x except x = 2.
Step-by-step explanation:
Given the functions are C(x) = 5/(x-2) and D(x) = (x+3)
Finding (C·D)(x) :-
(C·D)(x) = C(x) * D(x)
(C·D)(x) = 5/(x-2) * (x+3)
(C·D)(x) = 5(x+3) / (x-2)
(C·D)(x) = (5x+15) / (x-2)
Let y(x) = (C·D)(x) = (5x+15) / (x-2)
According to definition of functions, the rational functions are defined for all Real values except the one at which denominator is zero.
It means domain will be all Real values except (x-2)≠0 or x≠2.
Hence, only option B is correct, i.e. all real values of x except x = 2.
Answer:
$126.33
Step-by-step explanation:
$379/3 = $126.33
First you would do parenthesis according to the PEMDAS(Parenthesis, Exponents, Multiply, Divide, Add, Subtract) Rule
4 -2(-5a -10) = 30
4 + 10a + 20 = 30
Now you need to add 4 and 20 because they are on the same side
24 + 10a = 30
Now subtract 24 on both sides
24 + 10a = 30
-24. -24
10a = 6
Last divide 10 from both sides
10a/10. = 6/10
a= 6/10
Last simplify (optional but recommended)
a = 3/5 or 0.6
Hope this helped :)
A = 0.6
Answer:
X=61.2
Step-by-step explanation:
x/85 = 72/100
x*100/8500 = 6120/8500
x*100 must equal 6120 therefore x must be 61.2 because 61.2 * 100 is 6120
