Answer:
The acceleration is exactly 40 mi/h² as shown
Explanation:
Given;
initial velocity of the car, u = 30 mi/h
final velocity of the car, v = 50 mi/h
change in velocity, ΔV = v - u
ΔV = 50 mi/h - 30 mi/h = 20 mi/h
initial time, t₁ = 2:00 PM
final time, t₂ = 2:30 PM
Change in time, Δt = t₂ - t₁
Δt = 2: 30 - 2:00 = 30 mins = 0.5 hour
Acceleration is given as change in velocity per change in time;
a = ΔV / Δt
Therefore, the acceleration is exactly 40 mi/h² as shown.
Answer:
he longer ramp has more mechanical advantage for it requires less force to push up a mass while being over a longer period of time. Its called Mechanical Advantage because say you had to lift a car up 1-meter. you cannot simply pick it up, but over a long enough slope you would be able to because you can apply a small force over a longer distance
Explanation:
Answer:
576 joules
Explanation:
From the question we are given the following:
weight = 810 N
radius (r) = 1.6 m
horizontal force (F) = 55 N
time (t) = 4 s
acceleration due to gravity (g) = 9.8 m/s^{2}
K.E = 0.5 x MI x ω^{2}
where MI is the moment of inertia and ω is the angular velocity
MI = 0.5 x m x r^2
mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg
MI = 0.5 x 82.65 x 1.6^{2}
MI = 105.8 kg.m^{2}
angular velocity (ω) = a x t
angular acceleration (a) = torque ÷ MI
where torque = F x r = 55 x 1.6 = 88 N.m
a= 88 ÷ 105.8 = 0.83 rad /s^{2}
therefore
angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s
K.E = 0.5 x MI x ω^{2}
K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules
a) The motion along the vertical direction and the motion along the horizontal direction.
b) The object remains in the air for a time period of 2usin(θ)/g.
Any object that is thrown in the air when gravity is acting on it is called a projectile. The motion of this projectile is called projectile motion.
When the projectile is thrown in the air at some angle θ, then there are two independent motions taking place at the same time. First is the component of motion along the vertical direction along which gravity acts. Second is the component of motion along the horizontal direction along which the object moves with a constant velocity. No force acts along the horizontal direction. The horizontal motion does not affect the vertical motion and the converse is also true. So these are independent of each other.
The time of flight is the time during which a projectile remains in the air. This time of flight is calculated using the formula,
T=2usin(θ)/g
where T is the time of flight, u is the initial velocity and g is the acceleration due to gravity.
Hence, the object remains in the air for a time period of 2usin(θ)/g.
Learn more about projectile.
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Answer:
F = 7.143 kN
Explanation:
given,
time taken to apply break = 1.05 s
car slows down from 15 m/s to 9 m/s
mass of the car = 1250 Kg
force is equal to the change in momentum with respect to time.
F = -7142.85 N
F = - 7.143 kN
Force is acting opposite direction of velocity of car i.e. the sign is negative.
