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aleksandrvk [35]
4 years ago
6

Suppose a car is traveling in the negative x-direction and comes to a stop. What is the sign of that car’s acceleration? How do

you know?
Physics
1 answer:
Oduvanchick [21]4 years ago
7 0

We have equation of motion v = u + at

Where v = final velocity, u = initial velocity, a = acceleration, and t = time

In this case car is travelling in -x direction

Velocity of car = displacement / time

Since displacement value is increasing in negative x axis it's initial velocity is negative

And it's final velocity is zero since it comes to rest, and time is also positive

So, v= u+ at => 0 = -u + at

   So, a = u/t

Which is positive and along positive X - direction

You might be interested in
2) A 20 kg mass moving at a speed of 3 m/s is stopped by a constant force of 15 N. How many seconds must the force act on the ma
hammer [34]

Take the object's starting direction of motion to be the positive direction, so that a stopping force acts in the opposite direction. By Newton's second law, the object undergoes an acceleration <em>a</em> such that

-15 N = (20 kg) <em>a</em>

Solve for <em>a</em> :

<em>a</em> = - (15 N) / (20 kg) = -0.75 m/s²

The object's velocity <em>v</em> at time <em>t</em> is then given by

<em>v</em> = 3 m/s + (-0.75 m/s²) <em>t</em>

so the time it takes for the object to slow to a rest is

0 = 3 m/s + (-0.75 m/s²) <em>t</em>

<em>t</em> = (3 m/s) / (0.75 m/s²) = 4.0 s

3 0
3 years ago
A man starts from rest and accelerates at 4.00 m/s2. If he covers a distance of 525 m, how long does he accelerate?
rosijanka [135]

Answer:

16.2 s

Explanation:

Given:

Δx = 525 m

v₀ = 0 m/s

a = 4.00 m/s²

Find: t

Δx = v₀ t + ½ at²

525 m = (0 m/s) t + ½ (4.00 m/s²) t²

t = 16.2 s

5 0
3 years ago
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
yaroslaw [1]

Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

6 0
3 years ago
There is no( ) in time between the action and the reaction
Lesechka [4]
There is no (gap) in time between the action and the reaction

hope that helps:)
4 0
4 years ago
How much did the temperature change between 10 a.m. and 1 p.m.?
yanalaym [24]

First take note that you're figuring 10am and 1pm. Their temperatures are 77 degrees and 83 degrees

To solve subtract 83-77=6

So it rose 6 degrees.

4 0
4 years ago
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