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3 years ago

14

A car travels at 65 miles per hours. Going through construction it travels at 3/5 this speed. Write this fraction as a decimal a

nd find the speed.

1 answer:

olga nikolaevna [1]3 years ago

6 0

3/5 = 6/10 = 0.6
0.6×65=39
Car travels 39 miles per hour through construction.

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The diameter of the circle above is 100 cm. What is the circumference of the circle<br> ?

Paladinen [302]

Answer: 100pi

Step-by-step explanation:

Look at attachment

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3 years ago

The managers of franks snack shack buys hamburgers in packages of 30 and hamburger buns in packages of 24. He cannot buy part of

Andreas93 [3]

Answer:

He has to buy 4 packages of hamburgers in packages of 30 and 5 packages of hamburgers in packages of 24

Step-by-step explanation:

First we have to calculate the least common multiple (LCM) of 24 and 30

We will calculate the LCM of 24 and 30 by prime factorization method

24 = 2*2*2*3 = $2^{3} * 3^{1}$

30 = 2*3*5 = $2^{1} *3^{1}* 5^{1}$

LCM = $2^{3}* 3^{1}*5^{1}$

LCM = 120

So number of hamburger buns = 120

Therefore, he must buy 120/24 = 5 packages of hamburgers in packages of 24 and he must also buy 120/30 = 4 packages of hamburgers in packages of 30

4 0

3 years ago

5n+4=39 find the value of n that makes this equation true

Bond [772]

5n + 4 = 39
5n = 39 -4
5n = 35
n = 35:5
n = 7

4 0

3 years ago

Read 2 more answers

What is the range of the function shown on the graph above?

AleksandrR [38]

Answer:

-9≤y≤8

Step-by-step explanation:

The range is the output values

Y goes from -9 to 8

-9≤y≤8

7 0

3 years ago

If y-3x=9, 7x+y=25, what is the value of x and y?

lianna [129]

$\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?$

$\bold{\rm{Solution}} \text{: We'll solve this by substitution method}$

$\dashrightarrow y - 3x = 9 \\ \\ \dashrightarrow \boxed{y = 9 + 3x } \qquad .. \sf eq(1)$

$\text{we got the value of y now getting the value of x}$

$\looparrowright 7x + y = 25 \\ \\ \looparrowright 7x = 25 - y \\ \\ \looparrowright \boxed{x = \frac{25 - y}{7}} \qquad .. \sf eq(2)$

$\text{Now, putting y = 9 + 3x in eq(2)}$

$\hookrightarrow x = \frac{25 - y}{7} \\ \\ \hookrightarrow x = \frac{25 - 9 + 3x}{7} \\ \\ \hookrightarrow 7x = 25 - 9 + 3x \\ \\ \hookrightarrow 7x - 3x = 16 \\ \\ \hookrightarrow 4x = 16 \\ \\ \hookrightarrow x = \frac{16}{4} \\ \\ \star \quad \boxed{ \green{ \frak{ x = 4}}}$

$\text{Now we know the value of x, for getting y we need to put x in eq(1)}$

$: \implies y = 9 + 3x \\ \\ : \implies y = 9 + 3(4) \\ \\ : \implies y = 9 + 12 \\ \\ \star \quad \boxed{\frak{ \green{y = 21}}}$

$\text{Hence, values of x and y are} \: \frak{ \green{4}} \: \text{and} \: \frak{ \green{21}} \: \text{respectively}.$

4 0

2 years ago