The simplest form is 46xy
Since 46 can not be factor out, there is only one x which stay there, and is 5 so the two pairs of y will be canceled and one y left.
Answer:

Step-by-step explanation:
Kindly refer to the image attached in the answer region for labeling of triangle.
<em>AB </em><em>= 16
</em>
<em>BC </em><em>= 19</em>
<em>AC </em><em>= 15
</em>

We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e.
.
Formula for <em>cosine rule</em>:

Where
<em>a</em> is the side opposite to
,
<em>b</em> is the side opposite to
and
<em>c</em> is the side opposite to
.

Similarly, for finding the value of <em>y:</em>

Hence, the values are:

Total Interest charged
=principle×interest rate×time
I=prt
I=45,580×0.04×1
I=1,823.2
Answer:
yes
Step-by-step explanation:
-1ft is greater then -5ft
Answer:

Step-by-step explanation:
GIVEN: A space telescope on a mountaintop is housed inside of a cylindrical building with a hemispheric dome. If the circumference of the dome is
, and the total height of the building up to the top of the dome is
.
TO FIND: what is the approximate total volume of the building.
SOLUTION:
let the height of the mountaintop be 
As the dome hemispherical.
circumference of a hemisphere 



total height of the building up to the top of the dome 


Volume of building 

as radius of mountain top is same as dome
putting values


Hence the total volume of the building is