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Zielflug [23.3K]
3 years ago
14

Two triangles are similar only if they share a congruent angle and two congruent sides adjacent to the angle.T/F explain plz

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0
That's false.  If they share a congruent angle and the sides adjacent to it are
also congruent, then the triangles are also congruent.  In order for them to be
similar, all that's necessary besides the congruent angle is that each side
adjacent to it be in the <em>same ratio</em> between the two triangles.
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Answer/Step-by-step Explanation:

1. 3x + y = 11 => equation 1

5x - y = 21 => equation 2

Subtract equation 2 from equation 1 to eliminate y variable

3x + y = 11

5x - y = 21

-2x = - 10

Divide both sides by -2

-2x/-2 = -10/-2

x = 5

Substitute x = 5 into equation 1 or 2:

3x + y = 11 => equation 1

3(5) + y = 11

15 + y = 11

y = 11 - 15 (subtraction 15 from each side)

y = -4

Solution: x = 5, y = -4

2. 5x + 12y = -34 => equation 1

2x + 4y = -12 => equation 2

Multiply equation 1 by 2, multiply equation 2 by 5.

2(5x + 12y = -34) => 10x + 24y = -68 => eqn 3

5(2x + 4y = -12) => 10x + 20y = -60 => eqn 4

Subtract eqn 4 from eqn 3

4y = -8

Divide both sides by 4

y = -2

Substitute y = -2 into equation 2

2x + 4y = -12 => equation 2

2x + 4(-2) = -12

2x - 8 = -12

2x = -12 + 8 (adding 8 to both sides)

2x = -4

Divide both sides by 2

x = -2

Solution: x = -2, y = -2

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