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julsineya [31]
3 years ago
11

4x+5/4x^3-2x^2-11x+5

Mathematics
2 answers:
posledela3 years ago
8 0
4x+5/4x³-2x²-11x+5 is simplified to 5/4x³-2x²-7x+5
den301095 [7]3 years ago
4 0
<span> 5x3 - 8x2 - 28x + 20 ———————————————————— 4 </span>
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1/4 times 8/8 what is the answer to this problem
Ann [662]
\frac{1}{4}
7 0
3 years ago
Clas...
vesna_86 [32]

Answer:

So, the original space of her garden was 20ftl + 4ftw. This makes her garden have a starting area of 80ft.

She then adds another 72ft (12ftl x 6ftw) which brings the total area to 152ft.

We have 152ft to work with here, if she wants to use 100 of those ft for vegetables, and the rest to plant fruits, we have to subtract 100 from 152 which gives us 52.

Answer:

The Fruits will take up 52ft of land.

Hope this helped!

6 0
3 years ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
Anna007 [38]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER, I HAVE A QUIZ THAT NEEDS TO GET DONE AND I HAVE NO IDEA HOW TO GET THIS!
Oliga [24]
There you go. cube root of smth is just the value to the power of one third.

4 0
3 years ago
Will mark brainliest!! Help Please!!!
expeople1 [14]

Answer:

f(x) = x^3 + x^2 - 33x + 63

Step-by-step explanation:

The zeros are x = 3, x = 3, x = -7.

A polynomial function with zeros x1, x2, x3, ..., xn has the form:

f(x) = (x - x1)(x - x2)(x - x3) ... (x - xn)

The zeros of this function are 3, 3, -7.

The function is:

f(x) = (x - 3)(x - 3)(x - (-7))

f(x) = (x - 3)(x - 3)(x + 7)

Now we multiply out the right side.

f(x) = (x^2 - 6x + 9)(x + 7)

f(x) = x^3 + 7x^2 - 6x^2 - 42x + 9x + 63

f(x) = x^3 + x^2 - 33x + 63

5 0
3 years ago
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