Question

The diameter of the base of the cone measures 8 units. The height measures 6 units. A cone has a diameter of 8 units and a height of 6 units. What is the volume of the cone?

Answer 1

Answer: V = 100.48

Step-by-step explanation:

To get this value, you need to know the formula of the volume of the cone, which is:

V = π*r^2*h / 3

Where:

r: cone radius

h: height

π: value of pi which is 3.14

Now the radius, is half the diameter of base of the cone so:

r = 8 / 2 = 4 units

Now we have all the data needed to get the volume of the cone, let's use the expression given above:

V = 3.14 * (4)^2 * 6 / 3

V = 3.14 * 16 * 6 / 3

V = 301.44 / 3

V = 100.48

Answer 2

Answer:

$V=32\pi (units)^{3}$

Also it can be expressed as $V=100.531(units)^{3}$

Step-by-step explanation:

Given a cone of radius ''R'' and height ''h'' we can calculate its volume ''V'' using the following equation :

$V=\pi .R^{2}.(\frac{1}{3}).h$ (I)

We know that the diameter ''d'' is equal to the radius ''R'' multiply by 2 ⇒

$d=2R$

We have the following data of the cone :

$d=8units$

$h=6units$

First we calculate the radius of the base ⇒

$d=2R$

$R=\frac{d}{2}=\frac{8units}{2}=4units$

$R=4units$

Now we replace the height and the radius of the base in the equation (I) ⇒

$V=\pi .(4units)^{2}.(\frac{1}{3}).6units$

$V=32\pi (units)^{3}$

Also we can expressed it as :

$V=32\pi (units)^{3}=100.531(units)^{3}$

$V=100.531(units)^{3}$