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adell [148]
3 years ago
7

P²- 4p - 32 = 0 solve by filling the square

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0
Did u want a picture of it or just the answer
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Jason is working on a Microsoft Excel worksheet and he wants to create a Print Preview shortcut. His teacher asks him to access
hichkok12 [17]

Answer:

<em>A.  New Tab (Custom) and New Group (Custom) </em>

<em>B.</em><em> New File Tab (Custom) and New Tab (Custom) </em>

<em>C.</em><em>  New Custom Group and New Command </em>

<em>D.</em><em>  New Custom Tab and New Command</em>

<em>The two tabs would be </em><em>[ file and print ] </em><em>if you are working the newest version of Microsoft office.</em>

6 0
3 years ago
Read 2 more answers
Can someone explain to me how to do this?
elena55 [62]
In the slope intercept form equation of a line (y=ax+b) a represents the slope, and b represents the intercept, which is -5. Thus, we know y=ax-5. The slope can be found by creating a fraction with the change in y value on top, and the change of x value on the bottom. If we have two points (4, 1) and (0, -5) we can put this into a fraction - \frac{-5-1}{0-4}, which simplifies down to -6/-4, or 3/2. Thus the answer is f(x)=\frac{3}{2}x-5<span />
6 0
4 years ago
Does 9 thousand equal 90 thousand
Dovator [93]

Answer:

no

Step-by-step explanation:

9000 has three zeros

whereas 90,000 has four zeros

when you multiply 9000 with 10 ,you get 90 thousand

6 0
3 years ago
Read 2 more answers
Find three consecutive off integers such that the difference of the third and second is
eduard
Ok so go to the top left and multiple it by 0 and then you will still get 0 so -0 + 10x 4
7 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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