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VladimirAG [237]
3 years ago
7

Which is a simplified form of the expression 2(y + 1) + 2(y – 2)? A. 2y + 1 B. 4y – 2 C. 2y – 1 D. 4y – 3

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

B) 4y-2

Step-by-step explanation:

2(y+1)+2(y-2)

2y+2+2y-4

2y+2y+2-4

4y+2-4

4y-2

NNADVOKAT [17]3 years ago
3 0
It’s B because when simplified it’s 2y+2+2y-4 then you add like terms and it becomes 4y-2 which is B
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Which one is the missing number? Help please
Readme [11.4K]
The answer is 2.
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3 years ago
How many different anagrams can you make for the word MATHEMATICS?
Alex73 [517]

Answer:

4989600

Step-by-step explanation:

The given word is MATHEMATICS

Number of letters in the given word is 11

there are 2 M's, 2 A's and 2 T's

the given word is arranged in 11! ways

three letters are repeating, so we divide by repeating occurrences

number of different arrangements =\frac{11!}{2!2!2!}

= 4989600

7 0
3 years ago
Ben's employer will reimburse him $0.13 per mile driven. If Ben drives 210.1 miles on a business trip, what is his mileage reimb
Helen [10]

Answer:

27.31

Step-by-step explanation:

Take the number of miles and multiply by the reimbursement rate

210.1 * .13

27.313

Round to the nearest cent

27.31

5 0
3 years ago
Find one terminating decimal and one repeating decimal between -1/2 and -1/3
Masteriza [31]
Terminating decimal:
-0.45
Repeating decimal:
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7 0
3 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
3 years ago
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