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VladimirAG [237]
3 years ago
7

Which is a simplified form of the expression 2(y + 1) + 2(y – 2)? A. 2y + 1 B. 4y – 2 C. 2y – 1 D. 4y – 3

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

B) 4y-2

Step-by-step explanation:

2(y+1)+2(y-2)

2y+2+2y-4

2y+2y+2-4

4y+2-4

4y-2

NNADVOKAT [17]3 years ago
3 0
It’s B because when simplified it’s 2y+2+2y-4 then you add like terms and it becomes 4y-2 which is B
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kotykmax [81]
It is 6y^4 this is the answer
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3 years ago
Subtract −7n+2 ​​from 2n−1 ​.
Wittaler [7]
The correct answer  is -5n+1   
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The daily profit P ​(in thousands of​ dollars) from the sale of televisions is a function of the number x of televisions sold ​(
scZoUnD [109]

Answer:

The break-even sales amounts​ is 36 or 224.

Step-by-step explanation:

Consider the provided function.

P= -5x^2 + 13x - 4

Where x is the number of televisions sold (in hundreds) and P is the profit.

We need to calculate the break-even sales amounts​.

the​ break-even sales amounts​ is the sales amounts that result in no profit or​ loss.

That means substitute P=0 and solve for x.

-5x^2 + 13x - 4=0

5x^2-13x+4=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a=4, b=-13 and c=4 in above formula.

x_{1,\:2}=\frac{-\left(-13\right)\pm \sqrt{\left(-13\right)^2-4\cdot \:5\cdot \:4}}{2\cdot \:5}

x_{1,\:2}=\frac{13\pm\sqrt{169-80}}{10}

x_{1,\:2}=\frac{13\pm\sqrt{89}}{10}

x=\frac{13+\sqrt{89}}{10},\:x=\frac{13-\sqrt{89}}{10}\\x\approx2.243, \ or\ x\approx 0.357

Therefore, the break-even sales amounts​ is 36 or 224.

7 0
3 years ago
What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
Mrrafil [7]

Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

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7 0
3 years ago
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I need help finding the formula..
KiRa [710]
X=first week
y=second week
z=third week
t=fourth week

18 more one 2nd week than 1st
x+18=y
x=y-18

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ttal=382

x+y+z+t=382
sub waht we know
x=y-18
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y-18+y+2y-4+92=382
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4y+70=382
minus 70 boht sides
4y=312
divide both sides by 4
y=78

78 customers
for equation read my answer slowly


8 0
3 years ago
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