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Brilliant_brown [7]
3 years ago
15

13 Points!!! The function f(x)= -3x^2+x^2+2x rises as x grows very large True Or False.

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
False if you take xyou can get answer
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2. What does y equal? *<br> y+3/4 = 6
kakasveta [241]

Answer:

3rd option

Step-by-step explanation:

Given

y + \frac{3}{4} = 6 ( multiply through by 4 to clear the fraction

4y + 3 = 24 ( subtract 3 from both sides )

4y = 21 ( divide both sides by 4 )

y = \frac{21}{4} = 5 \frac{1}{4}

6 0
3 years ago
Can people please help me on this
PtichkaEL [24]

the answer will be D

5 0
3 years ago
Rewrite the expression in the form x^n<br><br> Thank You
Lisa [10]

Answer:

See image below for answer:)

Step-by-step explanation:

FYI you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps and it's free.

3 0
3 years ago
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I am not good at algebra so I REALLY NEED HELP WITH THE PROBLEM 8n+4n^2-8n!
NeX [460]

Answer:

4n^2

Step-by-step explanation:

8n+4n^2-8n

The first 8n + the other 8n is 0 because you combine like terms

6 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
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