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3 years ago

In answering the following questions, assume that the angular acceleration is constant and nonzero: alpha not equal to zero.

1 answer:

8 0

I think the correct answer would be true. The quantity represented by theta is a function of time. This is because the rate of change of angular speed is constant which means the angular distance is changing with time. Hope this answers the question. Have a nice day.

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What is the distance between points (10, 7)(10, 7) and (2, 7)(2, 7) on a coordinate plane?

lawyer [7]

I am sorry i have no idea. :( But i can ask my brother who is in a higher grade than i. i will ask him when he gets home for you. :)

5 0

4 years ago

Question

sp2606 [1]

Given:

CH = 3960 miles

Altitude = 240 miles

To find:

The distance from the space station to the horizon.

Solution:

The reference image for answer is attached below.

Radius = 3960 miles

CD = CH = 3960

ED = 240

EC = CD + ED

= 3960 + 240

EC = 4200 miles

By Pythagorean theorem:

$E C^{2}=E H^{2}+C H^{2}$

$4200^{2}=E H^{2}+3960^{2}$

$17640000=E H^{2}+15681600$

Subtract 15681600 from both sides.

$17640000-15681600=E H^{2}+15681600-15681600$

$1958400=E H^{2}$

Taking square root on both sides, we get

$$1399.428=EH$

$$1400 \approx EH$

The distance from space station to the horizon is approximately 1400 miles.

8 0

4 years ago

#37 how do I do this

lora16 [44]

Sqrt(21x+1) = x+5
21x + 1 = x^2 + 10x + 25
x^2 - 11x + 24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8

8 0

4 years ago

The area of a _________ is half of the base multiplied by the height.

Alexus [3.1K]

Here, Area of Square = a²
Area of parallelogram = a * b
Area of Trapezoid = (a+b)/2 * h
Area of Triangle = bh/2

In question, it says "half of the base" not bases, so most appropriate answer would be: Option D) Triangle

Hope this helps!

7 0

4 years ago

Read 2 more answers

How do you use the half angle formula for <br> sin (5π/12)?

Mkey [24]

The half angle formula is:
sin x/2 = +/- √ (( 1-cos x ) / 2 )
5π/12 = 5π/6 : 2
sin 5π/12 = +/- √(( 1 - cos ( 5π/6)) / 2 )
cos 5π/6 = cos 150° = -√3/2
$sin (5 \pi /12) = \sqrt{ \frac{1+ \sqrt{3}/2 }{2} } = \\ =\sqrt{ \frac{2+ \sqrt{3} }{4} } = \\ = \frac{ \sqrt{2+ \sqrt{3} } }{2} =$
≈ 0.966 ( this is sin 5π/12 )

7 0

4 years ago