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3 years ago

Find the missing side.

Mathematics

2 answers:

Vitek1552 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

This is a right triangle, but note that you only know the measurement of one angle, which is 90 degrees.

Use the following formula to solve:

a² + b² = c²

In which:

a & b = shorter sides

c = hypotenuse

Plug in the corresponding numbers to the corresponding variables:

(3)² + (4)² = ?²

Solve. Remember to follow PEMDAS. First, solve the exponents, then add:

(3)² = (3 * 3) = (9)

(4)² = (4 * 4) = (16)

9 + 16 = ?²

25 = ?²

Isolate "?". Root both sides:

√(25) = √(?²)

? = √25 = √(5 * 5) = 5

Your missing side's measurement is 5.

maw [93]3 years ago

3 0

Answer:

The missing side is 5

Step-by-step explanation:

Step 1: Use Pythagorean Theorem to find the hypotenuse

Since we are given two sides, a and b, we need to find the hypotenuse or c.

Formula: $a^2 + b^2 = c^2$

Plug in

$(3)^2 + (4)^2 = c^2$

$9 + 16 = c^2$

$25 = c^2$

Square root both sides

$\sqrt{25} = \sqrt{c^2}$

$\sqrt{5^2} = c$

$5 = c$

Answer: The missing side is 5

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Answer:

h(-2) = -1

Step-by-step explanation:

h(x)=-2x-5

Let x= -2

h(-2)=-2*-2-5

= 4 -5

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3 years ago

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Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
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3 years ago

Read 2 more answers

Which expressions are equivalent??

Brilliant_brown [7]

Given:

The given expression is $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$

We need to determine the equivalent expression.

Option A: -1

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is not equivalent to -1.

Hence, Option A is not the correct answer.

Option B: 29

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to 29.

Hence, Option B is the correct answer.

Option C: $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Let us rewrite the given expression.

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, Option C is the correct answer.

Option D: $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Rewriting the expression, we get;

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent not to $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Thus, Option D is not the correct answer.

Option E: $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Multiplying the terms within the bracket, we get;

$2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Thus, Option E is the correct answer.

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3 years ago

A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s

777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

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Find the missing side.​

Find the missing side.