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Kamila [148]
3 years ago
9

What is -2x+5y=-6; -7x-2y=57

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0

Answer:

im not sure what you are asking

Step-by-step explanation:

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Claire deposited $500 into a savings account that earns 2.5% annual simple interest. If she keeps this amount in the account for
Snezhnost [94]

Answer:

Claire will earn $25 in interest after 2 years.

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Combine like terms (simplify)
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1) 8x-13
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Solve in the parentheses then label the ones with the same variable and solve those setting up the equation with variable first. Do check this I am not perfect.

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Please Help Me!!!!!!
Elanso [62]

Mimiwhatsup Answer is: H

The graph is correct and so is the table it's domain and ranges are correct I know I is not correct hope this helps!

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What is the gradient of the blue line
nirvana33 [79]

Answer:4

Step-by-step explanation:

When you look at the two lines, you can see that the blue line is steeper than the red line. It makes sense the value of the slope of the blue line, 4, is greater than the value of the slope of the red line, 14 .

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2 years ago
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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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