(01.02 LC) Simplify 8

There is a large number of cubes in a bag.

Alla [95]

Marked(10)/total = 3/20 (from sample)

total/10 = 20/3 (inverting the above proportion)

total = 10•20/3 = 200/3 ≈ 67

7 0

2 years ago

Can two obtuse angles be complementary

Norma-Jean [14]

Complementary angles are angles that add up to 90 degrees.

Obtuse angles are greater than 90 degrees, so there's no way
to add two of them together and get a sum that's smaller than
either one already is.

The answer to the question is 'No'.

8 0

3 years ago

Solve |x| + 7 < 4. ........................

Fynjy0 [20]

Hello :
|x| + 7 < 4.
|x| < 4.-7
|x| < -3
no reals solutions because for all reals x : |x| ≥ 0

8 0

3 years ago

A newspaper posted this question on its web "How often do you seek medical information online?" Of 1072 Internet users who cho

Lostsunrise [7]

Answer:

1. Option c

2. Option d

Step-by-step explanation:

This type of survey is includes a sample made up of voluntary responses. People only choose to or do not choose to respond.

This type of sampling method is most of the time unbelievable because generally only people with strong opinions about this particular questions will respond and it is usually towards the same direction as the question and this might not reflect the opinion of the whole population making the survey biased.

6 0

2 years ago

During halftime of a basketball game, a sling shot launches T-shirts at the crowd. A T-shirt is launched from a height of 4 f

Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is $4 + 64\cdot t - 16 \cdot t^{2}$

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

$h = 4 + 64\times 2 - \frac{1}{2} \times 32 \times 2^{2}$

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

$h =4 + 64\cdot t - \frac{1}{2} \times 32 \cdot t^{2} = 4 + 64\cdot t - 16 \cdot t^{2}$ .

6 0

2 years ago

(01.02 LC) Simplify 8 - (14)