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podryga [215]
3 years ago
10

What number should be added on both sides of the equation to complete the square x2 -6x =5

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0
The Answer wouldn't be any other number but 9. I took this test and got it right.
alisha [4.7K]3 years ago
3 0

Answer:

We should add 9 on the both sides of the given equation.

Step-by-step explanation:

Since, for making a perfect square on the left side of a quadratic equation,

We add the square of the half of the coefficient of x on both sides,

The given equation,

x^2-6x = 5

Here, the coefficient of x is 6,

Half of 6 = 3

Square of 3 = 9,

Thus, we should add 9 on the both sides of the given equation.

Verification :

x^2 - 6x + 9 = 5 + 9

(x-3)^2 = 14

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Answer:

$84.14

Step-by-step explanation:

Begin by multiplying 1.035 by 4.

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Add this to the original amount deposited, $80.

The answer is $84.14

8 0
3 years ago
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natita [175]
5 the answer I took the test
8 0
3 years ago
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s2008m [1.1K]

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5/8

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4 0
3 years ago
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered
inn [45]

Answer:

Step-by-step explanation:

2005 AMC 8 Problems/Problem 20

Problem

Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?

$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$

Solution

Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.

See Also

2005 AMC 8 (Problems • Answer Key • Resources)

Preceded by

Problem 19 Followed by

Problem 21

1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25

All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

5 0
2 years ago
HELP! WILL GIVE BRAINLIEST
likoan [24]

Answer: area 24 perimeter/circumstance 32 meters

Step-by-step explanation:

3 0
3 years ago
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