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Montano1993 [528]
3 years ago
11

Find (f+g)(x) when f(x)=x^3-2x^2+1 and g(x)=4x^3-5x+7

Mathematics
1 answer:
Oliga [24]3 years ago
8 0

Answer:

5x³ - 2x² - 5x + 8

Step-by-step explanation:

[ Refer to the attachment ]

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How do you answer this equation?<br> 5a - 12 = 48
IgorC [24]
Add 12 to both sides resulting in 5a = 60 and then divide both sides by 5 which results in a = 12 so your answer will be a = 12
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Heyy i REALLY need help with this pleaaaase hurry
Diano4ka-milaya [45]
1.3-slope
6/3 just divide if you need to put it in a decimal-A
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Is the m in mx+b=y the growth
Shalnov [3]

The "m" in y = mx + b is the <u>slope.</u>

It is the number of units a point goes up, down, left, or right each time. Making the line linear/straight.

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"rise" is the the number of units you go up(+) or down(-), "run" is the number of units you go to the right


For example, if your slope is:

\frac{1}{2}

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You are going up 3 units, and to the right 1 unit


-\frac{1}{2}

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4 0
3 years ago
Read 2 more answers
This trapezium is drawn on a centimetre grid.<br> Find the area of the trapezium.
aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

<u>From </u><u>the</u><u> </u><u>grid</u><u> </u><u>:</u><u>-</u>

\rm\implies Side_1 = 7 \ units

\rm\implies Side_2 = 3 \ units

\rm\implies \perp \ Distance =4  \ units

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times   \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm  Area = 20 \ unit^2}

3 0
3 years ago
What is 4 to the 7th power ?
bonufazy [111]
4^7=16,384 i  used a calulator

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3 years ago
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