Answer:
(no change)
Step-by-step explanation:
Recall that the average rate of change of a function
over the interval
is equal to
:
![\frac{h(b)-h(a)}{b-a}\\ \\\frac{h(6)-h(1)}{6-1}\\\\\frac{0-0}{5}\\ \\0](https://tex.z-dn.net/?f=%5Cfrac%7Bh%28b%29-h%28a%29%7D%7Bb-a%7D%5C%5C%20%5C%5C%5Cfrac%7Bh%286%29-h%281%29%7D%7B6-1%7D%5C%5C%5C%5C%5Cfrac%7B0-0%7D%7B5%7D%5C%5C%20%5C%5C0)
Hence, the average rate of change of the function
over the interval
is
, or no change.
L: length defective<span>, T </span>: texture defective.
Given that the strip is length defective, the probability that this strip is texture defective is given by
<span><span>P (TL) =P (T ∩ L)=0.008= 0.08.</span><span>P (L)0.1</span><span>| www.imali.info</span></span>
Answer:
The service line is J9263 x 300 to report a unit of 150(300x 0.5 mg = 150).
Step-by-step explanation:
The drug J9263 Eloxatin contains 0.5 mg oxaliplatain.
<u>For a infusion of 50 mg the unit reported for service line information is</u>:
- <em>Service line:</em> J9263 x 100
- <em>Unit reported for service line information:</em> 50 = 100 x 0.5 mg
Hence, for a infusion of 150 mg, the unit reported for service line information is:
- <em>Unit reported: </em> 150(300 x 0.5 mg = 150)
- <em>Service line information:</em> J9263 x 300
Therefore, if the physician provided 150 mg infusion of the drug instead of an injection the service line is J9263 x 300 to report a unit of 150(300x 0.5 mg = 150).
I hope it helps you!
We can let x be the number of boxes sold for the first week. We can as well express the number of boxes for the second and third week through x using the statements provided.
Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:
first week: x
second week: x + 5
third week: 2(x + 5)
Given that the total number of boxes sold for the three weeks is 431. We have
x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104
We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218
Answer:
first week: 104
second week: 109
third week: 218
i believe the answer is 14.14