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Vladimir79 [104]

3 years ago

5

The perimeter of a triangle is 76cm side of the triangle is twice as long as side b .side c is 1 cm longer than a side a .find t

he lenght of each side

1 answer:

stepladder [879]3 years ago

7 0

P= a+b+c = 76
side a = 2b = 30
side b = b = 15
side c = 2b + 1 = 31

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cestrela7 [59]

The coordinates of P' is (9, -6) and L' is (3, -1).

<h2>Given that</h2>

PL has endpoints P(4, −6) and L(−2, 1).

The segment is translated using the mapping (x, y) → (x + 5, y).

<h3>We have to determine</h3>

What are the coordinates of P’ and L’?

<h3>According to the question</h3>

PL has endpoints P(4, −6) and L(−2, 1).

The segment is translated using the mapping (x, y) → (x + 5, y).

The coordinates of point P after translation using mapping is,

$\rm P(x, \ y) - P'(x+5, y)\\
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P(4, -6) - P'(4+5, \ -6)\\
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2 years ago

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In triangle abc shown below side ab is 6 and side ac is 4

kaheart [24]

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

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3 years ago

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