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abruzzese [7]
3 years ago
5

The square root of 125 is between what two numbers

Mathematics
2 answers:
Otrada [13]3 years ago
6 0

The square root of 125 is in between 11 and 12. It is 11.1803.

wolverine [178]3 years ago
3 0
The square root of 125 is between 11(121) and 12(144)
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A situation can be represented by this inequality?<br><img src="https://tex.z-dn.net/?f=1.25x%20-%206.50%20%3E%2050" id="TexForm
DochEvi [55]

There are four different choices. Now we have to find which choice best expresses the inequality 1.25x-6.50>50

1.25x has positive sign so any statement that indicates earning like sells at the rate of 1.25 will match with expression 1.25x.

Now -6.50 has negative sign that means this quantity must be subtracted or represents loss of any kind.


Keeping above sign in mind and reading the given statementns, we see that only choice "a" first the given inequality.


Hence final answer is a).

6 0
3 years ago
Read 2 more answers
A washer and a dryer cost $995 combined. The washer cost $45 more than the dryer. What is the cost of the dryer?​
Talja [164]

When a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

The combined cost of a washer and a dryer = $995

Consider the cost of a dryer as x

The washer cost $45 more than the dryer.

The cost of the washer = x+45

Then the equation will be

x+x+45 = 995

2x+45 = 995

2x = 950

x = 950/2

x = 475

The cost of the dryer is $475

Hence, when a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

Learn more about equation here

brainly.com/question/1625308

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8 0
10 months ago
What is the constant term in the expansion of the binomial (x − 2)^4?
Marianna [84]

Answer:

the answer is a i think





3 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
If 32^2c= 8^c+7, what is the value of c
Leona [35]

\bf 32^{2c}=8^{c+7}~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^5\\ 8=2\cdot 2\cdot 2\\ \qquad 2^3 \end{cases}\implies (2^5)^{2c}=(2^3)^{c+7} \\\\\\ 2^{5(2c)}=2^{3(c+7)}\implies \stackrel{\textit{if the bases are the same, then so are the exponents}}{5(2c)=3(c+7)\implies 10c=3c+21} \\\\\\ 7c=21\implies c=\cfrac{21}{7}\implies c=3

3 0
2 years ago
Read 2 more answers
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