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Westkost [7]
3 years ago
10

Wich undefined term can contain parallel lines?

Mathematics
1 answer:
Luden [163]3 years ago
7 0
Planes are undefined terms. They can contain parallels. 

Have a nice day, brainliest would be fantastic

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103. Please help me!10 points! Thanks.
Inessa05 [86]
The formula for the surface area of a sphere is 4πr^2

This can be used in the following way, getting the diameter at 18.3:
18.3/2 = 9.15
Saying PI is 3.14 you can do this:

SA = 4*3.14*9.15^2 = 1051.6 m^2

Formula for volume is:
(4/3)πr^3

V = (4/3)*3.14*9.15^3 = 3207.2 m^3
8 0
3 years ago
Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
Ethan invested £500 in the bank for 2 years.
Anon25 [30]

Answer:

Step-by-step explanation:

I=PRT/100

40=(500XRX2)/100

R=(40X100)/500X2

R=4000/1000

R=4 percent/annum

3 0
3 years ago
What number goes in the highlighted box?
pentagon [3]
-15+7=-8
Adding numbers with different signs makes it subtraction and the answer will have the sign of the bigger number
3 0
3 years ago
Look at the picture. What is the solution WORTH 10 POINTS
Ivanshal [37]

The coordinates of the point intersection of lines (-1, -1)

If you want solve:

y = -2x - 3, y = 3x + 2

-2x - 3 = 3x + 2     |+3

-2x = 3x + 5     |-3x

-5x = 5     |:(-5)

x = -1

Put the value of x to the first equation:

y = (-2)(-1) - 3 = 2 - 3 = -1

x = -1, y = -1

3 0
3 years ago
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