A 18 gram sample of a substance that's used to detect explosives has a k value of0.125
1 answer:
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Answer:
Check the explanation
Step-by-step explanation:
let the money on bet is X.
probability of winning =18/38=9/19
probability of losing =(1-9/19)=10/19
expected outcome =probability *return =(
Expected value of return after one bet is =(9/19*x)-(10/19*x)=-1x/19
it is negative which is obvious cause casinos are there to earn money.
a) Our best strategy in this case as probability of winning is near by 50 %, we should place a bet of 1 $ each,and when we lose one bet consecutively we should bet twice the amount..
Cause two consecutive losses on black has less probability.
c) In case we have to reach 30 $ we have to use the same strategy as above.
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E =
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E =
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E =
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E =
= 2 × 0.0702
= 0.1404