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iris [78.8K]
3 years ago
10

The cost of staying one night at a hotel in amber city is $59. The cost of staying one night at a hotel in bear lake is $159. Fi

nd the amount saved on a 5 night stay in amber city instead of bear lake
Mathematics
1 answer:
Sloan [31]3 years ago
7 0
If you stay in amber city you waste $295 but if you go to bear lake your wasting around $795 so your saving $500
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Please answer quick!!
rewona [7]

Answer: B

Step-by-step explanation:

\frac{2}{7k}(k-7)

\frac{2k-14}{7k}

\frac{2k}{7k}-\frac{14}{7k}

\frac{2}{7}-\frac{2}{k}

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Find the value of X, please explain!
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All four angles are exterior angles of the quadrilateral.

We know that the sum of exterior angles of any polygon is 360 ° .

So we can add together the four angles and solve for x:
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erastovalidia [21]

Answer:

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Step-by-step explanation:

4 0
2 years ago
The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.
NISA [10]

Answer:

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=8.2 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.2 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

8 0
3 years ago
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Shelby wants to buy 10 yards of fabric that costs $2.49 per yard. How much money will Shelby need to purchase all the fabric? $2
nekit [7.7K]

Answer:

$24.90

Step-by-step explanation:

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