Answer:
1?
Step-by-step explanation:
Answer:
y=-2/5x+2
Step-by-step explanation:
Answer:
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
270 miles
Step-by-step explanation:
So is A is going faster than B so A will reach the destination first.
When will A reach it's destination?
Let's find out.
To solve this problem, the following will come in handy:
Speed=distance/time or time*Speed=distance or time=distance/speed .
time=distance/speed



So it will take bus A 6 hours to cover the distance of 390 miles.
How much time would have it taken bus B to reach that same distance?


So it would have taken bus B
hours to cover a distance of 390 miles.
So the time difference is
hours.
It will take
more hours than bus A for bus B to complete a distance of 390 miles.
So bus B traveled
miles (used the time*speed=distance) after bus A got to it's destination.
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
Answer:
x= -4 & y=-12
Step-by-step explanation:
multiply y=3x by 2
giving you 2y=6x
subtracting 2y=x+20 from 2y =6x
=> 5x=-20
dividing through by 5
=> x=-4
put x=-4 into y=3x
=> y=3(-4)
<em>y</em><em>=</em><em>-12</em>
<h3>
The combined weight of a car and truck is given as the polynomial P(W) = x³ + x² + 11 x + 300</h3>
Step-by-step explanation:
The weight of the car is given as:
P(C) = x² + 10 x + 200
The weight of the truck is given as:
P(T) = x³ + x + 100
Now, the combined weight of both vehicles is given as
= Weight of Car P(C) + Weight of Truck P(T)
P(W) = x² + 10 x + 200 + x³ + x + 100
= x³ + x² + (10 x + x)+ (200 + 100)
= x³ + x² + 11 x + 300
⇒ The combined weight of a car and truck is given as the polynomial P(W) = x³ + x² + 11 x + 300