Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
We need more detail I will help when i get a real question
Answer:
25 degrees
Step-by-step explanation:
In the picture attached, the lines and the angles are shown. There we can see that:
85° + 2x° + (x-10)° = 180°
75 + 3x = 180
x = (180 - 75)/3
x = 35°
∠3 and ∠(x-10)° are alternate interior angles, therefore they are congruent, so:
∠3 = x - 10
∠3 = 35 - 10
∠3 = 25°
√-1=i
13-√-18=
13-√(-1)(18)=
13-(√-1)(√18)=
13-(i)(3√2)=
13-3i√2
Step-by-step explanation:
Bc is also 20 answer is 400
