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3 years ago

I need some help please

Mathematics

1 answer:

Marina CMI [18]3 years ago

8 0

First divide the triangle in 2

then fine the area of one triangle and then the other

then finally add them together and you have your anwser

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Determine the solution to the system of equations graphed below and explain

lawyer [7]

If x - 4 ≥ 0, then |x - 4| = x - 4, so

G(x) = F(x) ⇒ 3x + 2 = (x - 4) + 2

⇒ 3x + 2 = x - 2

⇒ 2x = -4

⇒ x = -2

Otherwise, if x - 4 < 0, then |x - 4| = -(x - 4), so

G(x) = F(x) ⇒ 3x + 2 = -(x - 4) + 2

⇒ 3x + 2 = -x + 6

⇒ 4x = 4

⇒ x = 1

However,

• when x = -2, we have

G(-2) = 3(-2) + 2 = -4

F(-2) = |-2 - 4| + 2 = 8

• when x = 1, we have

G(1) = 3(1) + 2 = 5

F(1) = |1 - 4| + 2 = 5

so only x = 1 is a solution to G(x) = F(x).

7 0

2 years ago

Write an algebraic equation to represent the situation

8090 [49]

Answer:

C. 2d+3=12

Step-by-step explanation:

6 0

2 years ago

Graph the function y=√x+1-4. Which point lies on the graph?

nataly862011 [7]

The answer is C (-1,-4)
I got the answer by graphing the equation and plotting each the points down to see which one lies on the graph

8 0

2 years ago

Susan wants to buy cherries for a party. She has $8.00 to spend. Cherries are $2.75/kg. How many kilograms of cherries can Susan

OLga [1]

Answer:you would have to divide $8.00/$2.75 and it would equal $2.90

Step-by-step explanation:This may help and if it does please thank me in the comments.

3 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago