Answer:
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Step-by-step explanation:
If you know tangent of theta is 5/3 and it is in the 3rd quadrant, then you know the sides will be going in the negative direction and the real values of the sides would be -5/-3. You can use pythagorean theorem to figure out that the hypotenuse would be sqrt(5^2+3^2) = sqrt(34). Then you can use soh cah toa: sin = opp/hyp, cos=adj/hyp tan = opp/adj. You know that opp = -5, adj = -3, and hyp = sqrt(34) For cosine theta, it would be -3/sqrt(34) and csc is just 1/sin so csc would be hyp/opp = sqrt(34)/-5.
Since we know the sequence is quadratic, we expect the
-th term to have the general form

Plug in the first 3 known values of the sequence to form a system of equations.



Eliminating
gives


Eliminating
gives

Solving for
, we get


So, the
-th term of the sequence is

Pa, Pb,Pc,Ya, Yb,Yc,Ta, Tb, Tc
9 total outcomes choosing one balloon
The length of FG would be BC. This is because FG and BC corresponds on the shape letter sequence. This would mean that EF would be AB, that GH would be CD, and that HE would be DA.