To find f(2), look and see where the line crosses the Y axis, when The line is on X 2.
The line is on Y = -2, so the answer would be -2.
The first one is 2 the second one is 3
Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 × 
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed =
Average speed =
Average speed is 37.35 mi/h
The equation of the rotating light is an illustration of a secant function
The equation that represents the distance between the center of the circle and the light source is 
<h3>How to determine the equation</h3>
The equation is a secant function represented by

Where:
A represents the amplitude
So, we have:
--- the distance of the light from each square wall
B represents the period, and it is calculated as:

The light completes its full rotation every 6 seconds.
This means that,
T = 6
So, we have:

Simplify

Substitute values for A and B in 

Rewrite as a function

Hence, the equation that represents the distance between the center of the circle and the light source is 
Read more about trigonometry functions at:
brainly.com/question/1143565