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ahrayia [7]
3 years ago
16

In what form is carbon found in the atmosphere?

Physics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

Carbon is found in the atmosphere mostly as carbon dioxide.

Explanation:

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How to calculate energy needed for a change of state ​
Alenkasestr [34]

Answer:

change in temperature = (100 - 25) = 75.0°C.

change in thermal energy = mass × specific heat capacity × change in temperature.

= 0.200 × 4,180 × 75.0.

= 62,700 J (62.7kJ)

7 0
3 years ago
Read 2 more answers
The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a
Andreyy89

Answer:

3.6ft

Explanation:

Using= 2*π*sqrt(L/32)

To solve for L, first move 2*n over:

T/(2*π) = sqrt(L/32)

Next,eliminate the square root by squaring both sides

(T/(2*π))2 = L/32

or

T2/(4π2) = L/32

Lastly, multiply both sides by 32 to yield:

32T2/(4π2) = L

and simplify:

8T²/π²= L

Hence, L(T) = 8T²/π²

But T = 2.1

Pi= 3.14

8(2.1)²/3.14²

35.28/9.85

= 3.6feet

5 0
3 years ago
A light microscope allows for more magnification than electron microscope because it uses a beam of visible light. true false
Igoryamba

False because light microscopes have low resolve and magnification.

4 0
4 years ago
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet
Shtirlitz [24]

The average distance between the planet and the star is:

R=9.36*10^11 m

Orbital velocity  v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

As was already said, Earth is located roughly 150 million kilometres (93 million miles) from the Sun on average. It is 1 AU. Mars is on our fictitious football field's three-yard line. On average, the distance between the Sun and the red planet is around 142 million miles (228 million kilometres).

Learn more about average distance:

brainly.com/question/18366547

#SPJ4

The complete question is ''If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 10^30 kg, what is the average distance between the planet and the star? 1.43 × 10^9 m 9.36 × 10^11 m 5.42 × 10^13 m 9.06 × 10^17 m''.

4 0
1 year ago
A rifle is aimed horizontally at a target 47 m away. The bullet hits the target 2.3 cm below the aim point.
inna [77]

Answer:

Is your question asking for the muzzle velocity of the bullet?

Explanation:

I will assume it does

The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest

s = ½at²

t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s

v = d/t = 47/0.0685118 = 686.01242...

v = 690 m/s

3 0
2 years ago
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