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Sever21 [200]
4 years ago
14

A tied ball game goes into blank innings

Physics
1 answer:
vlada-n [284]4 years ago
4 0
Extra innings is the answer
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If a hockey player starts from rest and accelerates at a rate of 2.1 m/s2 how long does it take him to skate 30m
OLga [1]
Hello!

<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
</span>
Formula: S = S_{o} +  V_{o}* t + a* \frac{t^2}{2}

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²

Solving:
S = S_{o} + V_{o}* t + a* \frac{t^2}{2}
30 = 0 + 0*t + 2.1* \frac{t^2}{2}
30 =  \frac{2.1t^2}{2}
30*2 = 2.1t^2
60 = 2.1t^2
2.1t^2 = 60
t^2 =  \frac{60}{2.1}
t^2 \approx 28.5
t \approx  \sqrt{28.5}
\boxed{\boxed{t \approx 5.3\:s}}\end{array}}\qquad\quad\checkmark

Answer:
<span>C. 5.3s</span>
5 0
4 years ago
A soccer ball was kicked. It had the mass of .42 kg and acceleration at 25m/s. what was the force?
maw [93]
Force of the kick or the balls velocity
4 0
3 years ago
Read 2 more answers
The fact that large elliptical galaxies are much more common in the central regions of galaxy clusters than elsewhere in the uni
Alenkinab [10]

The fact that large elliptical galaxies are more common in central galaxy clusters suggests that collisions play a role in the formation of these galaxies.

<h3>What is galaxy formation?</h3>

Galaxy formation is a physical phenomenon where molecular clouds of dust concentrate and thus first generate stars.

Galaxy formation is a process that can be associated with collisions, at least for the formation of elliptical galaxies.

Collisions are a relatively frequent process in clusters (groups) of galaxies that are formed by crashes with other galaxies.

Learn more about galaxy formation here:

brainly.com/question/7348850

6 0
3 years ago
A catcher catches a 150g baseball traveling horizontally at 25 m/s. If the ball takes 20.ms to stop once it is in contact with t
rosijanka [135]

Answer:

The magnitude of the force exerted by the ball on the catcher is 1.9 × 10²  N

Explanation:

Hi there!

Let´s find the acceleration of the ball that makes it stop when caught by the catcher. The acceleration can be calculated from the equation of velocity considering that it is constant:

v = v0 + a · t

We know that initially the ball was traveling at 25 m/s, so, if we consider the position of the catcher as the origin of the frame of reference, then, v0 = -25 m/s. We also know that it takes the ball 20 ms (0.02 s) to stop (i.e. to reach a velocity of 0). Then using the equation of velocity:

v = v0 + a · t

0 m/s = -25 m/s + a · 0.020 s

25 m/s/ 0.020 s = a

Now, using the second law of Newton, we can calculate the force exerted by the catcher on the ball:

F = m · a

Where:

F = force.

m = mass of the ball.

a = acceleration.

F = 0.150 kg · (25 m/s/ 0.020 s) = 1.9 × 10²  N

According to Newton´s third law, the force exerted by the ball on the catcher will be of equal magnitude but opposite direction. Then, the force exerted by the ball on the catcher will have a magnitude of 1.9 × 10²  N.

3 0
4 years ago
If a spear is jabbeb exactly at that place where the fish appears in water, the fish is not killed
Korvikt [17]

You have learned your lesson well, Suhay. Your statement is correct.

The light rays from the fish BEND when they flow out of the water into the air. But our primitive brain still believes that the light rays flow STRAIGHT from the fish. The result is that the fish does not APPEAR to be at that place where it really is.

7 0
3 years ago
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