Question:
Teresa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 12 hours. When Teresa drove home, there was no traffic and the trip only took 8 hours. If her average rate was 20 miles per hour faster on the trip home, how far away does Teresa live from the mountains?
Do not do any rounding.
Answer:
480 miles
That is Teresa lives 480 miles from the mountains
Explanation:
Here we have
Distance D = Speed S × Time t
On her way to the mountain we have
D = S × 12
On her way back we have
D = (S +20)×8
Therefore, by comparing the two above equations, we have
S × 12 = (S +20)×8
Therefore, 12·S = 8·S +160 or
4·S = 160
Hence S = 160/4 = 40 miles/hour
Therefore, from D = S × 12, we have
D = 40 × 12 = 480 miles.
Answer:
<em><u>When</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>straight</u></em><em><u> </u></em><em><u>line</u></em><em><u>,</u></em><em><u> </u></em><em><u>it's</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>becomes</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>displacement</u></em><em><u>.</u></em><em><u> </u></em>
Explanation:
<em><u>Distance</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>actual</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>covered</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>displacement</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>covered</u></em><em><u>.</u></em>
<em><u>
</u></em>
<em><u>✌</u></em><em><u>Follow</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>❤</u></em>
<em><u>and</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>☺</u></em>
Answer:
P = 800 Pa
Explanation:
The pressure of water at the bottom of the pot can be given by the following formula:

where,
P = Pressure at the bottom of the pot = ?
ρ = density = 1000 kg/m³
h = height of water = 8 cm = 0.08 m
Therefore,

<u>P = 800 Pa </u>
Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive