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Anvisha [2.4K]
3 years ago
8

What do you measure with a spring scale?

Physics
1 answer:
goblinko [34]3 years ago
6 0
The answer would be weight in pounds
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Teresa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Teresa drove
Ksenya-84 [330]

Question:

Teresa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took  12 hours. When Teresa drove home, there was no traffic and the trip only took 8 hours. If her average rate was  20 miles per hour faster on the trip home, how far away does Teresa live from the mountains?

Do not do any rounding.

Answer:

480 miles

That is Teresa lives 480 miles  from the mountains

Explanation:

Here we have

Distance D = Speed S × Time t

On her way to the mountain we have

D = S × 12

On her way back we have

D = (S +20)×8

Therefore, by comparing the two above equations, we have

S × 12 = (S +20)×8

Therefore, 12·S = 8·S +160 or

4·S = 160

Hence S = 160/4 = 40 miles/hour

Therefore, from D = S × 12, we have

D = 40 × 12 = 480 miles.

7 0
3 years ago
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How is the weight of an object in a spaceship near the moon related to the distance that the spaceship is from the moon
larisa86 [58]
I think its the moons gravitational pull
3 0
3 years ago
Read 2 more answers
What is the condition for distance travelled by a body is equal to displacement ​
Simora [160]

Answer:

<em><u>When</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>straight</u></em><em><u> </u></em><em><u>line</u></em><em><u>,</u></em><em><u> </u></em><em><u>it's</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>becomes</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>displacement</u></em><em><u>.</u></em><em><u> </u></em>

Explanation:

<em><u>Distance</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>actual</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>covered</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>displacement</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>covered</u></em><em><u>.</u></em>

<em><u></u></em>

<em><u>✌</u></em><em><u>Follow</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>❤</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>☺</u></em>

6 0
4 years ago
One pot has a water height of 8cm. Calculate the water pressure at the bottom of the pot. They give g = 10N / kg p = 1000kg / m3
natima [27]

Answer:

P = 800 Pa

Explanation:

The pressure of water at the bottom of the pot can be given by the following formula:

P = \rho g h

where,

P = Pressure at the bottom of the pot = ?

ρ = density = 1000 kg/m³

h = height of water = 8 cm = 0.08 m

Therefore,

P = (1000\ kg/m^3)(10\ m/s^2)(0.08\ m)

<u>P = 800 Pa </u>

5 0
3 years ago
Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0
3 years ago
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