Solve by using the quadratic formula:
TexFormula1" title="4x { }^{2} - 5x = 3" alt="4x { }^{2} - 5x = 3" align="absmiddle" class="latex-formula">
1 answer:
Answer:
x = (5 + sqrt(73))/8 or x = (5 - sqrt(73))/8
Step-by-step explanation:
Solve for x over the real numbers:
4 x^2 - 5 x = 3
Subtract 3 from both sides:
4 x^2 - 5 x - 3 = 0
x = (5 ± sqrt((-5)^2 - 4×4 (-3)))/(2×4) = (5 ± sqrt(25 + 48))/8 = (5 ± sqrt(73))/8:
Answer: x = (5 + sqrt(73))/8 or x = (5 - sqrt(73))/8
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Step-by-step explanation:
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Add 4 on both sides.
In the equation there is a -4.
If -4+4=0, that is how you would get rid of the -4.
But, you need to add 4 to 29 to really get rid of the -4.
So, 29+4 is 33.
b=33
