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inn [45]
3 years ago
6

Jack and Tyler ate a total of 35 cupcakes Tyler ate 5 more than jack how many did each person eat

Mathematics
2 answers:
Reil [10]3 years ago
6 0
Tyler ate 20 jack ate 15 

Natali [406]3 years ago
3 0
Well Tyler ate 20, and Jack ate 15. I say this because I just subtracted the 5 cupcakes from the complete amount and got 30. Then I divided that by the two boys, and that gave them 15 each, but then I added back the 5 to one of the boy's totals (being Tyler's since he ate five more) And Tyler was left eating 20 while jack still ate 15.
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The diameter of a bicycle wheel is 2 feet.About how many revolutions does the wheel make to travel 2 kilometers?Explain.Hint 1 k
RSB [31]
We can work out the circumference of the wheel by using the equation

C = πd

C = π × 2
C = <span>6.28318530718
C = 6 feet

If 1km is 3280 feet, 2km is 6560 feet

6560 </span>÷ 6 = <span>1093.33333333 (recurring)
= 1093

Therefore the bike wheels rolls (approximately) 1093 times to cover 2km.
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3 years ago
PLZZ HURRY<br><br>q1) <br>Simplify. 6(5p^3 − 6p)
AlexFokin [52]

Answer:

30p^3−36p

Step-by-step explanation:

6(5p^3−6p)

=(6)(5p^3+−6p)

=(6)(5p^3)+(6)(−6p)

=30p3−36p

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3 years ago
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sveticcg [70]

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Step-by-step explanation:

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Find the total surface area of this triangular prism
Mnenie [13.5K]

Answer:

<h2><u><em>144 cm²</em></u></h2>

Step-by-step explanation:

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6 0
3 years ago
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The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?
QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

2x^{2}-8x=5

Taking 2 as common from left hand side, we get:

2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5

The square of difference is written as:

(a-b)^{2}=a^2 - 2ab + b^{2}                            Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0

Comparing the above equation with the given equation:

2(x-p)^{2}+q=0, we can say:

p = 2 and q= -13

6 0
3 years ago
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