Ask question

Ask question

All categories

I am Lyosha [343]

3 years ago

10

Kaylee is painting a design on the floor of a recreation room using equilateral triangles. She begins by painting the outline of

Triangle 1 measuring 52 inches on a side. Next, she paints the outline of Triangle 2 inside the first triangle. The side length of Triangle 2 is 75% of the length of Triangle 1. She continues painting triangles inside triangles using the 75% reduction factor. Which triangle will first have a side length of less than 26 inches?

1 answer:

Olegator [25]3 years ago

3 0

Triangle 4. There you go

You might be interested in

A triangle has an area of 900m^2 . If a parallelogram has the same height and base as the triangle, what is the area of the para

igor_vitrenko [27]

Answer:

area = 1800 m²

Step-by-step explanation:

area of one triangle = 900 m²

if a parallelogram has the same height and base as the triangle, then that means the area or the two triangle and shaped as a parallelogram

is twice the area given.

area = 900 * 2

area = 1800 m²

6 0

3 years ago

Mina uses 128 pounds of dog food to feed her 16 dogs. find the unit rate per dog

MAXImum [283]

The unit rate is 8 pounds per dog.

128 / 16 = 8

7 0

3 years ago

Read 2 more answers

Evaluate 1x + y, for x = 8 and y=-15.<br> 7 <br> -7<br> 23<br> -23

statuscvo [17]

Answer:

B) -7

Step-by-step explanation:

x+y

8+(-15)=8-15=-7

5 0

2 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Best answer gets brainliest!

nikitadnepr [17]

Answer: <u>Best answer gets brainliest!</u>

<h2>90+120= 210</h2>

Step-by-step explanation:

<u>Add the amount of students together!</u>

Hopefully this helps you!

-Keira

4 0

2 years ago

Read 2 more answers