Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer:
8.7
Step-by-step explanation:
Answer:
<h2>By angle sum property:</h2>
BAC+ABC+BCA=180°
90°+45°+x=180°
135°+x=180°
x=45°=BCA
<h2>since BCA=ABC=<u> </u>45° each </h2><h2>therefore,</h2>

<h2><em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
The circumference of a circle that was computed when the diameter is 3cm will be 9.426cm.
<h3>How to find the circumference?</h3>
The circumference of a circle of gotten by the formula:
C = 2πr or πd
where,
r = radius
d = diameter
Since the diameter is given as 3cm, the circumference will be:
= πd
= 3.142 × 3
= 9.426cm
In conclusion, the circumference of the circle is 9.426cm.
Learn more about circle on:
brainly.com/question/25938130