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miv72 [106K]
3 years ago
14

X^2 - 6x+ 5= -11 number and type of solutions

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

no real solutions

3±32i

Step-by-step explanation:

used quadratic formula

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garri49 [273]
What are the measurements

6 0
3 years ago
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KonstantinChe [14]

Answer:

do ur test by ur own understanding... xD

Step-by-step explanation:

<h3>all the natural numbers can be expressed in the form of the product of its prime factors.</h3>
8 0
3 years ago
What are the values of x and y if this equation is true?<br><br> 22(x + yi) + (28 + 4i) 72 – 62i
ASHA 777 [7]

Answer:

x = 2

y = -3

Step-by-step explanation:

The given equation is,

22(x + yi) + (28 + 4i) = 72 - 62i

By solving this equation further,

22x + 22yi + 28 + 4i = 72 - 62i

(22x + 28) + (22y + 4)i = 72 - 62i

Now both the sides of the equation is in the form of complex number,

By comparing real and imaginary parts given on both the sides,

22x + 28 = 72

22x = 72 - 28

22x = 44

x = 2

22y + 4 = -62

22y = -62 - 4

22y = -66

y = -3

Therefore, x = 2 and y = -3 are the values for which the given equation is true.

8 0
3 years ago
Which ordered pair is the solution to the system of equations?
SOVA2 [1]
To find the solution, we use the substitution method. 

x+y=-1
<span>x-3y=11
</span>
x+y = -1-y
  -y       

x = -1-y

Now apply the value of x into the other equation.

x-3y=11
-1-y-3y = 11

Combine like terms

-4y -1 = 11
       +1    +1
-4y = 12

-4y = 12
-4y/-4 = 12/-4
y = -3

Now, apply the value of Y to one equation to find x.

y = -3

x -3 = -1
   +3   +3  
 
x= 2

Now we have the value for both, x and y.
x = 2
y =-3

Final answer: A. <span>(2, −3)</span>
3 0
3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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