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Vitek1552 [10]
3 years ago
8

Martina has a sample of an unknown substance

Chemistry
1 answer:
LiRa [457]3 years ago
7 0
I think you forgot to add some of the question
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What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm
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Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error



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