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2 years ago

PLZ HELP IM NO SURE IF I PUT THE RIGHT ANSWER!!!!!!!!

Chemistry

2 answers:

Natasha2012 [34]2 years ago

7 0

Don’t worry, you’re right :)

leva [86]2 years ago

5 0

that is the correct answer don't worry :))

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Suppose a new liquid were discovered that is identical to water in every way except that it has a lower latent heat of fusion. W

faltersainse [42]

Answer:

It would take less time, because having a lower temperature of latent heat means that at a lower temperature it merges, therefore the closer it will be to the temperature of solification which is 0 degrees Celsius or Celsius ... It is then that it would solidify in less time than water

Explanation:

By acting and having all the same properties as water except for latent heat, it considers that the solidification temperature is 0 degrees Celsius like water.

3 0

3 years ago

Read 2 more answers

What characteristics determine how easily two substances change temperature? Check all that apply.

Vinil7 [7]

amount of time the two substances are in contact. area in contact between the two substances. specific heat of the material that makes up the substances. the density of the two substances in contact.

4 0

3 years ago

How many mL are in 7.3 dL?

Arte-miy333 [17]

Answer:

730 mL which is .73 L

Explanation:

8 0

3 years ago

A student dissolves 15.0 g of ammonium chloride(NH4Cl) in 250. 0 g of water in a well-insulated open cup. She then observes the

iren2701 [21]

Answer:

1) Endothermic.

2) $Q_{rxn}=4435.04J$

3) $\Delta _rH=15.8kJ/mol$

Explanation:

Hello there!

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

$Q_{rxn}=-(15.0g+250.0g)*4.184\frac{J}{g\°C}(16.0-20.0)\°C\\\\ Q_{rxn}=4435.04J$

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

$\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol$

Best regards!

4 0

3 years ago

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4

agasfer [191]

Answer:

$d=4.24x10^{-4}\frac{lb}{in^3}$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

$d=\frac{m}{V}$

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

$m=552.4g-464.7g=87.7g$

So that we are now able to calculate the density in g/mL first:

$d=\frac{87.7g}{27.8mL}=3.15g/mL$

Now, we proceed to the conversion to lb/in³ by using the following setup:

$d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}$

Regards!

6 0

2 years ago