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Oliga [24]
3 years ago
13

What are some or the characteristics of Wisconsin fast plants and zebra fish that make them ideal for use as model organisms?

Chemistry
1 answer:
coldgirl [10]3 years ago
6 0

Wisconsin fast plants have properties that make it easy to grow and see how organisms grow

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True or False;<br> aa is faster moving lava than pahoehoe?
frosja888 [35]

Answer:

It is false :l

Explanation:

Pahoehoe is a smooth and continuous lava crust. Pahoehoe forms when the effusion rate is low and consequently the velocity of lava flow is slow. Pahoehoe lava flow is usually at least 10 times slower than typical aa lava flow.

:/

7 0
3 years ago
Add the polynomials (7x^3-2x^2-12)+(3x^3-8x^2+10x)
laiz [17]

Answer:

10 x ^3 − 10 x ^2 + 10 x − 12

Explanation:

4 0
3 years ago
How many moles of MgSiO3 are in 237g of the compound?
Anna35 [415]
For this, we first calculate molecular weight of MgSiO₃:
Atomic masses:
Mg = 24
Si = 28
O = 16

Mr = 24 + 28 + 16 x 3
Mr = 100

moles = mass / Mr
moles = 237 / 100
moles = 2.37
6 0
3 years ago
Given that hclo4 is a strong acid, how would you classify the basicity of clo−4?
Mandarinka [93]
As a conjugate base of a strong acid,ClO4-would be classified as having a negligible basicity. The basicity of a chemical species is normally expressed by the acidity of the conjugate acid. The basicity of an acid is the number of hydrogen ions, which can be produced by one molecule of the acid. 
8 0
3 years ago
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0
3 years ago
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