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Oliga [24]
3 years ago
13

What are some or the characteristics of Wisconsin fast plants and zebra fish that make them ideal for use as model organisms?

Chemistry
1 answer:
coldgirl [10]3 years ago
6 0

Wisconsin fast plants have properties that make it easy to grow and see how organisms grow

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What does "hidden phenomena" mean in science?
dusya [7]

Answer:

it's means two plural phenomenon and object or aspect known for through the sentence rather than by dot or intuition a temporal or spout temporal object of sensory experience as discussion from a nominal

6 0
3 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
goblinko [34]
 The balanced equation for

 Ca(OH)2  +  H3PO4→  Ca3(PO4)2  +  H2O    is

 3 Ca(OH)2  +2 H3PO4→  Ca3(Po4)2  +  6  H2O

3 moles of  Ca(OH)2  reacted with 2  moles of H3PO4  to  form  1 mole  of  Ca3(PO4)2   and  6  moles  of H2O
6 0
3 years ago
Read 2 more answers
I NEED THE ANSWER TO NUMBER 3 pleaseee
postnew [5]

Answer:

density = 2.769 g

Explanation:

4.26 times 0.65

3 0
3 years ago
If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
n200080 [17]
<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span> 
</span>
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
              = 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴ 
where Ca is the acid concentration 
5 0
3 years ago
A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the h
lapo4ka [179]
Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5




8 0
3 years ago
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